Question

A body is projected vertically up.What is the distance in it's last second upward motion

Answer 1

Answer:

it's g/2

Explanation:

hope it helps u bro..........

Answer 2

Answer:

Answer:

$\huge\mathsf\pink{Solution:-}$

→The distance covered by the object in its last second of its upward motion its equal to the distance covered in the first second of its downward motion.

Hence, s = ½ gt² = ½ × 10 × 1 = 5m