Question

A body is projected vertically up with a certain velocity, covers a height in last second of ascending is
m. (g = 11 m/s2)​

Answer 1

Answer:

Explanation:

Time taken by the ball to reach the maximum height is  

v=u−gt

t=  g /u

​  

 

Distance travelled in n th second is  

s=u+   a /2 (2n−1)

s=u− g /2 (2  u/g  −1)

Therefore, the magnitude of the displacement in the last second of its upward motion =  g /2

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