Question

a body is projected vertically up with a velocity49m/s find max.height,time of flight,time of ascent and velocity when it is at a height of 60m?

Answer 1

Answer:

maximum height = u^2/2g = 49 x 49 / 2 x 9.8 = 122.5 m

time of flight = 2 x u / g = 2 x 49 / 9.8 = 10 sec

time of ascent = u / g = 5sec

v^2 - u^2 = 2as

v^2 - 49 x 49 = 2 x -9.8 x 60

v^2 = 1225

v = 35 -> velocity at 60 m

Explanation: