Question

a body is projected vertically up with speed u its velocity at half its maximum height is

Answer 1

See,

Maximum Height = H =$u^2/2g$

By equation of motion,

$v^{2} =u^{2} -2g(H/2)$

$v^2=u^2-2g(u^2/4g)$

$v^2=u^2-u^2/2$

$v^2=u^2/2$

therefore,

$v= u/\sqrt{2}$

Answer 2

i hope this answer help u