Question

A body is projected vertically up with u. Its velocity
at half its maximum height is
(1) u÷2
(2) u^2÷2
(3) root 2u
(4) u÷root2
please answer this question faster​

Answer 1

Answer:

4

Explanation:

by work energy theorem max height is u^2 /2g it's half of distance is u^2/4g then by using third equation of motion it's velocity is u/root2