Question

A body is projected vertically up with velocity ‘u’ . Velocity at half of its maximum height and 3/4 of its maximum height are

Answer 1

Answer:

l

Explanation:

at max height , velocity (v)= 0

=> 0 = u²-2gh => h= u²/2g............(1)

___________

for a height h/2 , velocity (v) = √u²- (u²/4g)×2g

= u /√2 m/sec...............(2)

____________

at a height 3h/4, velocity= √u²- (3u²/8g) ×2g

= u/2 m / sec ..........(3)

Answer=> (1) u/√2m/s,

(2) u/2 m/s