a body is projected vertically upward if T1 and t2 be the times at which it is at height H above the point of projection
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a body is projected vertically upwards from the ground.It is found at the same elevation at t=3 and t=7s after projection.Find the projection speed.
Answer.
U=g÷2(t1+t2)
=5×(3+7)
=5×10
=50m/s.
U=g÷2(t1+t2)
=5×(3+7)
=5×10
=50
Hope this helps you dear friend\
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