Question

A body is projected vertically upward with speed 10 m/s and other at same time with same speed in downward direction from top of a tower.The magnitude of acceleration of first body w.r.t. second is {take g=10m/s2}
1)zero
2)10m/s2
3)5m/s2
4)20m/s2
That 2 is square

Answer 1

The magnitude of acceleration is taken place with g and second body has a downward acceleration with respective of g.

This denotes first body and utilize with same acceleraton and no one is accelerating with respect to another.

The magnitude of acceleration is zero because there is no change in velocity by practical. It is ultimately 0 by perfect measurement.

Answer 2

Answer:

correct answer is zero

Explanation:

In first case,

u=10m/s ,v=0 ,a=a1, and t=1sec (constant)

a1=v-u/t

a1=0-10/1

a1 =-10m/s^2

In second case,

u=0, v=10m/s ,a=a2,t=1sec (constant)

a2=10-0/1

a2=10m/s^2

Hence, magnitude of second body w.r.t. first body =10-10=0