A body is projected vertically upward with speed 10m/s and other at same time with same speed in downward direction from the top of a tower.The magnitude of acceleration of first body w.r.t second is?
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Solution:
ACCELERATION is uniform in the both cases.
For the body projected upwards acceleration is in downward direction = -g
For the body falling down , acceleration is downward =g
The magnitude of ACCELERATION of first body with respect to second = g-(-g)
=2g.
ACCELERATION is uniform in the both cases.
For the body projected upwards acceleration is in downward direction = -g
For the body falling down , acceleration is downward =g
The magnitude of ACCELERATION of first body with respect to second = g-(-g)
=2g.
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