Question

a body is projected vertically upward with speed 40 metre per second the distance travelled by body in last second of upward journey is​

Answer 1

Answer:

Time taken to go up is given by

v = u - gt

0 = 40 -10t

t = 4s

Hn = distance traveled in nth second = u - (g/2)*(2n-1)

H4 = 40 - (5)*(7) = 40 - 35 = 5m

In the last second while going up, the body traveled 5m