Physics, asked by shaikh283, 1 year ago

A body is projected vertically upward with the velocity of 29.4 m.s it come back to the point of projection after ​

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Answered by AmritRaaj
4

s = 0 \\ ut -  \frac{1}{2} gt {}^{2}  = 0 \\ u -  \frac{1}{2} gt = 0 \\ t =  \frac{2u}{g } \\ t = 2 \times 29.4 \frac{1}{9.8}

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