Question

A body is projected vertically upwards and it is at height ''h'' after 2 seconds and again after 8 seconds. The height h is
a) 50 m
b)40m
c)125m
d)80m
please solve by elaboration.​

Answer 1

Answer:

80 m

Explanation:

we know that

h = (1/2 )* g* t1 *t2. (gravitational constant 10m/s^2)

h= 1/2 * 10 * 2* 8

h= 80m

Answer 2

Please refer to the attachment for the answer

Note :- For more clarification refer the answer below.

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Given :-

• T1 = 2 seconds
• T2 = 8 seconds

Formula used :-

• $h = \frac{1}{2} \times g \times t1 \times t2$

Where,

h = height

g = gravitational constant = 10m/s²

Solution :-

Putting the values, we get,

$= > h = \frac{1}{2} \times 10 \times 2 \times 8 \\ = > h = 10 \times 8 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > h = 80 \: metre \: \: \: \: \: \: \: \: \: \: \:$

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Hope it helps you mate! :)