Question

a body is projected vertically upwards eith velocity 49m/s.find
a. maximum height
b. time of ascent
c. time of flight
d.velocity when it is at a height of 60m
(g=9.8m/s)

Answer 1

so here u =49m/s,v=0,a=10

b. time of ascent=u/g=49/10=4.9s(5) approx

c.time of flight=2u/g=98/10=9.8s=10approx

a. S=49×10+1/2×10×100

=490+500=990m

d. S=60,u=49,t=10

S=v+u/2×t

60=v+49/2×10

120=v+49×10

12=v+49

v=12-49

v=-37m/s