a body is projected vertically upwards . If t1 and t2 be the times , at which it is at a height h above the point of projection while ascending and descending respectively then maximum height reached by the body is
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Let v be initial velocity of vertical projection and t be the time taken by the body to reach a height h from ground.
Here, u=u,a=−g,s=h,t=t
Using, s=ut+
2
1
at
2
, we have
h=ut+
2
1
(−g)t
2
or gt
2
−2ut+2h=0
∴t=
2g
2u±
4u
2
−4g×2h
=
g
u±
u
2
−2gh
It means t has two values, i.e.,
t
1
=
g
u+
u
2
−2gh
t
2
=
g
u−
u
2
−2gh
t
1
+t
2
=
g
2u
or u=
2
g(t
1
+t
2
)
.
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