Question

A body is projected vertically upwards. the times corresponding to height h while ascending and while descending are t1 and t2 respectively. then velocity of projection is

Answer 1

Ut1/2 where is velocity of the body

Answer 2

Apply simple Newton’s second law of equation,h = ut – ½ gt^2Now this is aquadratic in t time.ssolve it as quadratic and get 2 values of t .i.e. t1 and t2.And then mulitply them that is t1t2 and equate it to 2h/g.get h value.