Question

A body is projected vertically upwards with a speed of 20 ms ms. The distance travelled by it after 3 sec is​

Answer 1

Answer:

We use the equation s = ut+1/2 at²

u = 20 m/s

a = - 10 m/s²

t = 3 sec

S = 20×3 + 1/2 (-10)(3)²

S = 60 + (-45)

S = 15 m

Distance travelled is 15 m.

#WMK

Answer 2

Answer:

hey mate!

15 m

Explanation:

With the second law of motion~~

s=ut+½at²

where we have-

u=20

t=3

a=-10 ~opposite direction

s=?

substitute the values

s=60-45

s=15m

Hope it helps!!