Question

A body is projected vertically upwards with a velocity 40m/s. The maximum height reached by the body is what? (g=10m/s^2)
Plsss answer soon....

Answer 1

ANSWER:

maximum height = 80 meter

Explanation:

given that,

A body is projected vertically upwards with a velocity 40m/s.

so,

here,

initial velocity of the body = 40 m/s

let the maximum height at which ball will reach be h

so,

final velocity of ball at maximum height = 0 [body will stop for a moment]

now,

we have,

initial velocity(u) = 40 m/s

final velocity(v) = 0 m/s

since body is against the gravitational force

so,

gravitational acceleration(g) = -10 m/s²

by the motion formulae of gravitation

v² = u² + 2gh

now,

putting the values,

(0)² = (40)² + 2(10)h

20h + 1600 = 0

20h = -1600

h = -1600/20

h = -80

negation of height shows the height against the gravitational force

so,

The maximum height reached by the body at which ball will reach

= 80 meter

Answer 2

☞ A body is projected vertically upward with a velocity.

Means it's initial velocity (u) is 40 m/s

• u = 40 m/s

☞ We have to find the maximum height reached by the body.

• Height (h) = ?

• Acceleration due to gravity (g) = 10 m/s² ________ [GIVEN]

_______________________________

• Now...

$\boxed{\bold{ {v}^{2} \: - \: {u}^{2} \: = \: 2as}}$

Here ;

v = 0 m/s

u = 40 m/s

a = g = 10 m/s²

s = h = ?

• Put the given values in above equation.

=> (0)² - (40)² = 2 × (10) × h

=> - 1600 = 20 h

=> 20h = -1600

=> h = $\dfrac{-1600}{20}$

=> h = - 80 m

Height is negative means it is against gravitational force. So, we neglect it's negative value. And take it positive.

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The maximum height reached by the body is 80 m.

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