Question

A body is projected vertically upwards with
a velocity of 10 m/s. It reaches the
maximum vertical height h in time t. In first
t/2 time interval the height covered is :-​

Answer 1

Answer:

u=10m/s

v=0

v=u - gt

-u=-gt

10=10×t

t=1 sec.

Now using

H=ut-1/2gt^2

H=10×1/2-1/2×10×(1/2)^2 (For t/2 tine

H=5-5/4

H=15/4 m

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