Question

a body is projected vertically upwards with a velocity of 36m/s. calculate the height and time... when the velocity reduced to 24m/s.​

Answer 1

Answer:

given ,

initial velocity = 36 m/s

final velocity   ( which we will take to solve the question ) = 24 m/s

We use the first equation of motion ie v = u+at

it means t = v-u / a

here , a = -g = -10 m/s²

24 = 36 - 10t

24 - 36 = 10t

-12 = -10t

( - ) gets cancelled

10t = 12

t = 12/10

 = 1.2 sec

Now we will use the second equation of motion to find the distance ie

S = ut + 1/2at²

S = 36×1.2 - 1/2×10×1.2×1.2         [ as 1.2² can be represented as 1.2×1.2 ]

   = 43.2 - 7.2

   = 36 m

Hence , the distance will be 36 m and time will be 1.2 sec.

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