Physics, asked by Shankarnaren2876, 1 year ago

a body is projected vertically upwards with speed 10 m/s other at same time with speed in downward direction. the magnitude of acceleration of first body w.r.t. second is
ANSWER IS ZERO BUT HOW??

Answers

Answered by Aayushi826
1
body 1                                           body 2
U=10 m/s                                  U = 0       ( in case o free falling object)
V=0                                            A= 10m/s sq (ACCELERATION DUE TO GRAVITY)
A= V-U/t                                   (here acceleration is negative)
=0 - 10 /1sec
A= -10 m/sec sq
 
but in question it asked abt magnitude so for both the body magnitude wud be 10 m /s sq.
so A1 w.r.t A2
is
A1-A2 (10 - 10 = 0)
= 0 (ans)......
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