a body is projected vertically upwards with speed 10 m/s other at same time with speed in downward direction. the magnitude of acceleration of first body w.r.t. second is
ANSWER IS ZERO BUT HOW??
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body 1 body 2
U=10 m/s U = 0 ( in case o free falling object)
V=0 A= 10m/s sq (ACCELERATION DUE TO GRAVITY)
A= V-U/t (here acceleration is negative)
=0 - 10 /1sec
A= -10 m/sec sq
but in question it asked abt magnitude so for both the body magnitude wud be 10 m /s sq.
so A1 w.r.t A2
is
A1-A2 (10 - 10 = 0)
= 0 (ans)......
U=10 m/s U = 0 ( in case o free falling object)
V=0 A= 10m/s sq (ACCELERATION DUE TO GRAVITY)
A= V-U/t (here acceleration is negative)
=0 - 10 /1sec
A= -10 m/sec sq
but in question it asked abt magnitude so for both the body magnitude wud be 10 m /s sq.
so A1 w.r.t A2
is
A1-A2 (10 - 10 = 0)
= 0 (ans)......
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