Question

a body is projected vertically upwards with velocity u crosses. it crosses point in its journey at a height h twice just after 1 and 7 second the value​

Answer 1

Explanation:

h=ut−

2

1

gt

2

h=u(1)−

2

1

g=u−

2

g

.....(1)

h=u(7)−

2

1

g(7)

2

=7u−

2

49g

.....(2)

Equating (1) & (2)

u−

2

g

=7u−

2

49g

24g=6u

u=4g

⇒u=40 m/s