Question

A body is projected with a speed of 40 m/s vertically upwards from the ground . what is the maximum height reached by the body take g = 10 m/s 2

Answer 1

Explanation:

u = 40 m/s

a=g=10m/s²

vertically upward so g=. -10m/s²

v=0m/s as the body is going to stop after some time

maximum height = s

by 3rd equation given by galeleo

v²- u²= 2as

0²- 40² =2 x -10 x s

- 1600 = -20 s

s = 80 m

therefore the maximum height reached by the body is 80m ..

Answer 2

Answer:

¤ Given:

Speed of the body vertically = 40 m/s

Final velocity = 0

Acceleration due to gravity = 10 m/s² or - 10 m/s²

¤ To find:

The maximum height of the body

¤ Taken:

To find the maximum height use the third equation of motion:

$\boxed{v²-u²=2aS}$

Where,

v = Final velocity

u = Initial velocity

a = Acceleration due to gravity

S = Diplacement

( Here , initial velocity is 40 m/s )

( And the displacement is the total height covered by the body )

¤ Solution:

$Taken,v²-u²=2aS$

$\Rightarrow{(0)²-(40m/s)²=2×-10m/sS}$

$\Rightarrow{1600=-20m/sS}$

$\Rightarrow{1600/20=S}$

$\Rightarrow{80m=S}$

¤ Answer:

So , the maximum height of the body is 80 m .

¤ Extra information:

First equation of motion:

$Vf=Vi+at$

Where,

Vf = Final velocity

Vi = Initial velocity

a = Acceleration

t = Time

Second equation of motion:

$S=ut+\frac{1}{2}at²$

Where,

S = Distance travelled

u = Initial velocity

t = Time

a = Acceleration