Question

a body is projected with a speed of 50 m/s difference in their max height is 30 m find it's range
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Answer 1

Answer:

A body is projected with a velocity of 30 Metre per second at an angle of 30 degree with the vertical find the maximum height time of flight and horizontal range

Can you find the maximum height, time of flight and horizontal range? Solution: Given: = 30 m/s and angle of projection is 30 with the vertical = 60 above the horizon. Time(t) = ( == =>t = (30 ==> t = 2.651098175 sec to reach the top (max height).

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Answer 2

Answer:

300

Explanation:

Given: = 30 m/s and angle of projection is 30 with the vertical = 60 above the horizon. Time(t) = ( == =>t = (30 ==> t = 2.651098175 sec to reach the top (max height). A body projected at an angle with the horizontal has a range of 300m.