Question

A body is projected with a velocity 100m/s vertically upwards find max height , velocity got halved of the max height , distance travelled in last 2s of its.......

Answer 1

u = 100 m/s

v=0

a= -10 ms^-2

s =???

v2=u2+2as

0=u^2 -20s

20s =( 100)^2

20s = 10000

s =500m .

Now ,

u = 100 /2= 50

t = 2s

a=10

Now , s = ut+ 1/2at^2

→ s = 50×2 - 1/2×10×2×2

→s =100-20=80