Question

a body is projected with a velocity 60m/s at 30 degree to horizontal. its initial velocity is 30 root 3 +30j. then its velocity afer 3 seconds will be
A)20i+20root3j
B)30i
C)10 root 3 j
D)30 root 3 i

i want with clear explanation

Answer 1

Answer:

Velocity along X-AXIS remains same which is ucosθ = 60(cos30°) = 60√3/2 =30√3m/s

______________________________

velocity along Y-AXIS

Vy=Vsinθ-gt

=> Vy=60(sin30) - 10(3)

=> Vy = 60/2 - 30 =30-30=0

_______________________________

THUS ... at time , t=3s ....

Vy=0m/s and Vx= 30√3m/s

_______________________________

NOTE:-

as Vy at t=3sec=> body is at its maximum height

and time of flight will be 2(3)=6sec

______________________________

Read more on Brainly.in - https://brainly.in/question/5421970#readmore