Question

A body is projected with a velocity 60ms" vertically upwards the distance travelled in last second of its motion is [ g = 10 m/s]

Answer 1

Answer:

5m

Explanation:

v=u+at

-60/10=t

t=6 sec

in: 5 seconds=S=60*5-5*25=175m

in 6 seconds=S=60*6-5*36=180m

Distance in last second=5m