Question

A body is projected with a velocity of 2× 11.2 km/s from the surface of earth . The velocity of the body when it is escaped the gravitational pull of earth

Answer 1

I can give you the path to solution

Just consider Conservation of Mechanical Energy

You can find the distance where the Gravitational pull ends let it be h you have given velocity u and take the final velocity as v

1/2m$u^{2}$ = mgh + 1/2m$v^{2}$

You can easily find v

Answer 2

Here have a look :)