Question

a body is projected with a velocity of 20m/s at an angle of 30°with horizontal. find the maximum range of the projected body

Answer 1

this is the answer
hope it helps

Answer 2

Answer:

R=34.67m

Explanation:

concept= formula for the range,R= u^2sin2θ/g

given - initial velocity ,20m/s

angle,θ= 30°

find - find the maximum range

explanation

R=u^2sin2θ/g

R=(20)^2sin2(30)/10

: sin2(30°) = sin60°= √3/2

R= 400*√3/2/10

R=34.67m

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