Question

A body is projected with a velocity of 20m/s in a direction making an angle of 60 degree with the horizontal. calculate its position and velocity after 5 second.​

Answer 1

Time of flight of the particle T=2×102×20×3

T=23 seconds

i)Position in X-direction after 0.55 second X=10×0.55=5.5m

In Y-direction ,Y=103×0.55−5×(0.55)2

Y=8m

position=(5.5,8)

ii)Velocity in X direction =10m/s

Velocity in Y direction v=u−gt

v=103−10×0.55=11.8m/s

velocity =10i^+11.8j^

hope it helps...uu