A body is projected with a velocity of 20ms in a direction making an angle of 60 degree with horizontal. Calculate its postistion and velocity after 5sec?
Answers
Answer:
u = 20 m/s. ? = 60°.
Let position be (x, y) after time t = 0.5 s
There is no acceleration along horizontal direction and there is accleration due to gravity along vertical direction.
We know that,
The equation of projectile gives the vertical distance travelled.
Thus, the position of body after 0.5 s is (x, y) = (5 m, 7.44 m)
The x component of velocity is
The y component of velocity is
Thus, the velocity of the body after 0.5 s is
u = 20 m/s. ? = 60°.
Let position be (x, y) after time t = 0.5 s
There is no acceleration along horizontal direction and there is accleration due to gravity along vertical direction.
We know that,
The equation of projectile gives the vertical distance travelled.
Thus, the position of body after 0.5 s is (x, y) = (5 m, 7.44 m)
The x component of velocity is
The y component of velocity is
Thus, the velocity of the body after 0.5 s is
u = 20 m/s. ? = 60°.
Let position be (x, y) after time t = 0.5 s
There is no acceleration along horizontal direction and there is accleration due to gravity along vertical direction.
We know that,
The equation of projectile gives the vertical distance travelled.
Thus, the position of body after 0.5 s is (x, y) = (5 m, 7.44 m)
The x component of velocity is
The y component of velocity is
Thus, the velocity of the body after 0.5 s is
u = 20 m/s. ? = 60°.
Let position be (x, y) after time t = 0.5 s
There is no acceleration along horizontal direction and there is accleration due to gravity along vertical direction.
We know that,
The equation of projectile gives the vertical distance travelled.
Thus, the position of body after 0.5 s is (x, y) = (5 m, 7.44 m)
The x component of velocity is
The y component of velocity is
Thus, the velocity of the body after 0.5 s is