Question

a body is projected with a velocity of 98m/s find maximum height reached​

Answer 1

Heya !!!

This is your answer.

Given :

u = 98 m/s

g = -9.8 m/s². ( As it is thrown upwards)

v = 0 (As it will stop after reaching heighest point)

Using

2gs = v² - u²

2 × -9.8 × s = - (98 × 98)

s = (98 × 98)/(2 × 9.8)

s = 98 × 5

s = 490 m.

Now, Using

v = u + at

0 = 98 - 9.8 × t

t = 10 s

Hope You Got It

Answer 2

Answer:

490 m

Explanation:

u = 98 m/s

a = g = -9.8 m/s²  (In this case)

v = 0 m/s  (highest point)

v² = u² + 2ah

0² =  98² + 2(-9.8)h

98² = 2 x 9.8 x h

h = 98² ÷ 19.6

h = 98 x 5

h = 490 m