A body is projected with an intial velocity 20ms at60 with the horizontal. Its intial velocity vector is
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2
Answer:
10i + 10√3j
Explanation:
The initial velocity has two components
Horizontal component
ux = (uCos∅)i
= (20Cos60)i
= (20 × 1/2)i
= 10i
Vertical component
uy = (uSin∅)j
= (20Sin60)j
= (20 × √3/2)j
= 10√3j
So, initial velocity vector is
u = 10i + 10√3j
Answered by
2
Answer:
Hey mate plzz refer to the attachment
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