Question

A body is projected with initial velocity of 40 m/s and at an angle of 30°with the horizontal. Calculate (i) time of flight and (i
i) horizontal range of projectile.(assume g= 10 m/s^2)
take this point bro in attachment​

Answer 1

Here is your answer:-

Time of flight= 4 seconds

Horizontal range= 138.56m

Given

Initial velocity= 40m/s

projection angle=30°

Accn. due to gravity= 10

As Per formula= 2usinθ/g

T= 2×40× sin30°/10

T= 4 seconds

Now, R= u^2sin2θ/g

Putting value in the above formula we get

R= 1600× sin60°/10

R= 1385.6/10

R= 138.56 m Ans

Hence the correct answer of your question is 138.56m

Answer 2

(i) With centre Y and any radius draw an arc which cuts ZY at P and XY at Q. (ii) With centre Q and radius more than 1/2(PQ) draw an arc. (iii) With centre P and same radius draw an arc which cuts the previously drawn arc at R. (iv) Join YR and produce it to any point S. Thus YS is the bisector of ∠XYZ.

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