Question

A body is projected with kinetic energy K at an angle of 45 with the vertical. Its kinetic energy at the highest point of its trajectory will be:Required to answer. Single choice.
2k
k
k/2
k/4​

Answer 1

Answer:

Kinetic Energy , E=

2

1

mv

2

At the highest point , vertical component of velocity becomes zero and only the horizontal is left that is given by

u

x

=ucosθ

θ=45°,socosθ=

2

1

u

x

=

2

u

Kinetic energy E at the highest point =

2

1

m(

2

u

)

2

=

2

E