a body is projected with speed 20m/s and at an angle of 45 with the horizontal. the horizontal range
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Motion in horizontal direction:
x=20cos45
o
t
t=
20cos45
x
...(1)
Motion in vertical direction:
y=20(sin45
o
)t−
2
1
gt
2
-(2)
putting value of t in equation (2) from (1) we get
y=x−
40
x
2
(m)
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Answer:
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