Question

A body is projected with the speed u horizontally frm the top of a tower . Find the horizontal displacement of the particle when the magnitude of vertical component of velocity is equal to the magnitude of horizonal component of velocity.

Answer 1

Answer:

When the body strikes the ground,

tan45

o

=

v

x

v

y

⇒

18

v

y

=→v

y

=18ms

−1