Question

A body is projected with the velocity of 50 m/s at an angle of 30o with the vertical. Calculate (i) height (ii) time of flight (iii) horizontal range of projectile. (g = 10 m/s2)​

Answer 1

Answer:

height : 125m, time of flight = 3.54s, horizontal range = 88.39m

Explanation:

velocity in x = vx = +25 m/s

velocity in y = vy = +25$\sqrt{2}$  m/s

acceleration in x = 0 m/$s^{2}$

acceleration in y = -10 m/$s^{2}$

height = s = -$vy^{2}$/2*a = -1250/(-10) =  125m

time of flight = t = vy/a = -25$\sqrt{2}$/(-10) = 3.54 s

horizontal range = vx*time = 25*(25$\sqrt{2}$/10) = 88.39m