Question

A body is projected with the velocity of 60 m/s at an angle of 30°
with the horizontal. Calculate :
(i) Maximum height
( ii ) Time of fight
(iii) Horizontal range of projectile. (assume g =10m/s2 ).​

Answer 1

Answer:

Maximum height attained by projectile is increased by10%.

Let h be the maximum height attained by the projectile. Then

h=

2g

u

2

sin

2

θ

R=

g

u

2

sin2θ

∴

h

R

=

g

u

2

sin2θ

=/

2g

u

2

sin

2

θ

=

(sin

2

θ)/2

2sinθcosθ

=4cotθ

Therefore,

R

ΔR

=

h

Δh

Hence, percentage increase in R

percentage increase in height h=5%