Question

A body is projected with velocity 25 m/s, the
distance travelled by it in the 3second its motion
is (g = 10 m/s2)
(1) Zero
(2) 2.5 m
(3) 1.25 m
(4) 7 m​

Answer 1

Answer:

answer is zero answer is zero

Answer 2

ANSWER:

The velocity of the projected body when thrown in the air is given as 25 m/sec.

The time taken by the for the calculation of the distance travelled is 3 sec

The acceleration of the object when the object is travelling in the air is taken as a = g =  

$10 m / \sec ^{2}$

The distance taken is

$S=u t+\frac{1}{2} g t^{2}$

$S=25.3+\frac{1}{2} .10 .(3)^{2}$

$S=75+5 \times 27$

S = 210 m

Therefore, the distance covered by the object in 3 sec at a speed of 25 m/sec is 210 m.