Question

A body is projected with velocity 60 m/s at 30to the horizontal. The velocity of the body after 3 seconds is

Answer 1

Answer:

Velocity along X-AXIS remains same which is ucosθ = 60(cos30°) = 60√3/2 =30√3m/s

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velocity along Y-AXIS

Vy=Vsinθ-gt

=> Vy=60(sin30) - 10(3)

=> Vy = 60/2 - 30 =30-30=0

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THUS ... at time , t=3s ....

Vy=0m/s and Vx= 30√3m/s

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NOTE:-

as Vy at t=3sec=> body is at its maximum height

and time of flight will be 2(3)=6sec

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hope it helpful.....