a body is projected with velocity u=50ms at an angle of 37 degree
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Explanation:
H = u²(sinФ)²/2g
= (50)²(3/5)²/20
= 2500*9/500 = 45
After reaching maximum height, the object should have a free fall .
V²=u²+2*g*H'
= 0 + 20*65 =1300
So, v =√1300 = 10√13
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