Question

A body is projected with velocity u at an angle of projection theta with the horizontal

Answer 1

if A body is projected with velocity u at an angle $\theta$ with horizontal.

then, velocity after time t, $v=ucos\theta\hat{i}+(usin\theta-gt)\hat{j}$

Time of flight , T = $\frac{2usin\theta}{g}$

horizontal range, R = $\frac{u^2sin2\theta}{g}$

maximum height attained by body, H = $\frac{u^2sin^2\theta}{2g}$

trajectory of motion of body, $y=xtan\theta-\frac{gx^2}{2u^2cos^2\theta}$ this is standard form of parabolic equation. so, path of body must be parabolic.

⇒ in case of projectile motion, acceleration along horizontal direction will be zero and acceleration along vertical direction will be acceleration due to gravity which always directs vertically downward.