Question

A body is projected with velocity u such that it's horizontal range and maximum vertical heights are same . The maximum height is​

Answer 1

ANSWER

Lets consider u= initial speed of the projectile

θ= angle of projection

According to question,

H=R

2g

u

2

sin

2

θ

=

g

u

2

sin2θ

sinθ.sinθ=2×2sinθ.cosθ

sinθ=4cosθ

tanθ=4

As we know that, 1+tan

2

θ=sec

2

θ

cos

2

θ

1

=1+16=17

cos

2

θ=

17

1

sin

2

θ+cos

2

θ=1

sin

2

θ=1−cos

2

θ

sin

2

θ=1−

17

1

=

17

16

Maximum height, H=

2g

u

2

sin

2

θ

H=

2g

u

2

17

16

H=

17g

8u

2