Question

A body is projectiles with a velocity of
20ms at 50° to the horizontal. Find time of
light ​

Answer 1

Answer: Initial Velocity Vo = 20 ms-1,

θ = 50o

Time of flight, t = 2V0sinθg

= 2×20×sin5009.8

= 3.126 s.

Maximum Height reached, H = V2osin2θ2g

= (20)2sin25022×9.8

= 11.97 m.

Horizontal Range R = v20sin2θg

= 202sin100o9.8

= 40.196 m.

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Answer 2

Answer:

here's your answer

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