Question

a body is released from a certain height was observed to cover 78.4m in last two seconds before hitting the ground.Find the height feom which it was released, G(9.8m/s²)

Answer 1

use second and third laws of motion

Answer 2

Here you go... First you find initial velocity for distance during last 2 seconds. The same initial velocity becomes the final velocity for the distance right on the top(before last two seconds). You must find this using 2nd law of motion. Once you find initial/final velocity, calculate distance from the top(before last two seconds) using third law of motion. Once distance is derived, add s1+s2 to derive total distance covered / distance from top. Thats it, Thank you.