Question

A body is released from height h above the ground which takes ‘t’ seconds to reach the ground. The position of the body after t/2 seconds is

Answer 1

Answer:

Answer of this question will be x= h/4 where x is distance covered in t/2 sec.

Answer 2

Answer: It will be at a distance of 3h/4 from the ground.

Explanation:

We know,

H = ut + 1/2gt² -----------------------(1)

Here as it is released, u will be equal to zero.

t is the time taken to cover h distance

Therefore equation 1 becomes

H = 1/2gt²

2H/g = t²

Now let S be the distance covered by the body in time t/2

Now,

S = 1/2g×(t/2)² -------------(2) (since u=0)

Putting the value of t² in equation 2 we get,

S = H/4

Therefore it will be at a distance of

(H - H/4) = 3H/4 from the ground.