a body is released from rest from a height find its speed at t =1 second and T =2 second and t= 3 second
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Answer: at t= 1s........v=10 m/s
at t=3 s ........v=20 m/s
at t=3s...........v=30 m/s
Explanation:
v=u+at
u=0 since released from rest
at t=1 s
v=0+(g×1)..........where g is acceleration due to gravity which is equal to 9.8 (approx. 10)
v= 0+10= 10 m/s
at t=2 s
v= 0+ (10×2)=20 m/s
at t=3 s
v= 0+ (10×3)= 30 m/s
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