Question

A body is released from rest from a height. Find its speed at t1= 1 sec, t2= 2 sec, t3= 3sec?

Answer 1

Acceleration due to gravity (g) = $\( 9.8 \frac{m}{s^2}\)$

v = gt

v (after 1 second) = $\(9.8 \times 1\)$

v (after 1 second) = $\( 9.8 \frac{m}{s}\)$

v (after 2 second) = $\(9.8 \times 2\)$

v (after 2 second) = $\( 19.6 \frac{m}{s}\)$

v (after 3 second) = $\(9.8 \times 3\)$

v (after 3 second) = $\( 29.4 \frac{m}{s}\)$

$\(v_1 = 9.8 \frac{m}{s}, v_2 = 19.6 \frac{m}{s}, v_3 = 29.4 \frac{m}{s}\)$