Question

a body is released from the top of a tower 80m high . where will it be after 2 seconds​

Answer 1

Answer:

80/2=40m/sec

Explanation:

I guess the information is not sufficient

Answer 2

Answer-

60 Meters if you take g=10m/s^2

61.4 Meters if you take g=9.8m/s^2

Explanation:

See I'm explaining it by taking g=9.8.

You can take the value you wish to

Now,

the body was released so initially it was at rest, therefore u=0

Also, a=9.8

Now,

Distance=s=ut+1/2at^2

S=0*2+1/2*9.8*2*2=19.6

Now total height=80m

Position = total height - distance covered =80-19.6=61.4m

Therefore object is 61.4m above the ground.

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