Question

a body is released from the top of a tower of height 50 m. find the velocity with which the body hits the ground.​

Answer 1

Answer: 31.22 m/s

Explanation:

Assuming free fall and applying equation of kinematics

v^2 = u^2 + 2gs

Here u^2 = initial speed = 0

v^2 = 2 ×9.8 ×50

v^2 = 980

v = 14 × 2.23

= 31.22 m/s

Answer 2

Answer:

s=50

g=9.7

v2=2(9.7)(50)

v2=970

v=√970

v=31.22